b^2+0,171b-0,342=0

Solution for b^2+0,171b-0,342=0 equation:

b^2+0.171b-0.342=0

a = 1; b = 0.171; c = -0.342;
Δ = b2-4ac
Δ = 0.1712-4·1·(-0.342)
Δ = 1.397241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.171)-\sqrt{1.397241}}{2*1}=\frac{-0.171-\sqrt{1.397241}}{2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.171)+\sqrt{1.397241}}{2*1}=\frac{-0.171+\sqrt{1.397241}}{2}
$